Question #228738

Calculate the Karl Pearson’s coefficient of correlation from the following pairs of values and interpret the result: Values of X 12 9 8 10 11 13 7 Values of Y 14 8 6 9 11 12 3  


Expert's answer

Xˉ=∑iXin=707=10\bar{X}=\dfrac{\sum_iX_i}{n}=\dfrac{70}{7}=10

Yˉ=∑iYin=637=9\bar{Y}=\dfrac{\sum_iY_i}{n}=\dfrac{63}{7}=9

SSXX=∑i(Xi−Xˉ)2=∑iXi2−n⋅Xˉ2SS_{XX}=\sum_i(X_i-\bar{X})^2=\sum_iX_i^2-n\cdot\bar{X}^2

=728−7(10)2=28=728-7(10)^2=28


SSYY=∑i(Yi−Yˉ)2=∑iYi2−n⋅Yˉ2SS_{YY}=\sum_i(Y_i-\bar{Y})^2=\sum_iY_i^2-n\cdot\bar{Y}^2

=651−7(9)2=84=651-7(9)^2=84



SSXY=∑i(Xi−Xˉ)(Yi−Yˉ)=∑iXiYi−n⋅XˉYˉSS_{XY}=\sum_i(X_i-\bar{X})(Y_i-\bar{Y})=\sum_iX_iY_i-n\cdot\bar{X}\bar{Y}

=676−7(10)(9)=46=676-7(10)(9)=46

r=SSXYSSXXSSYY=462884≈r=\dfrac{SS_{XY}}{\sqrt{SS_{XX}}\sqrt{SS_{YY}}}=\dfrac{46}{\sqrt{28}\sqrt{84}}\approx

≈0.948504\approx0.948504

0.7<r≤10.7<r\leq1 means a strong positive correlation.



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