Consider the following information
Period 1 2 3 4 5
Forecast 63 72 86 71 60
Actual 57 60 70 75 70
The mean absolute deviation M AD is
1. 552
2. 9:6
3. 48
4. 98
5. 96
MAD=∑i=1n∣yt−Ft∣nMAD=∣57−63∣+∣60−72∣+∣70−86∣+∣75−71∣+∣70−60∣5=6+12+16+4+105=9.6MAD = \frac{\sum^n_{i=1} |y_t -F_t|}{n} \\ MAD = \frac{|57-63|+|60-72|+|70-86|+|75-71|+|70-60|}{5} \\ = \frac{6+12+16+4+10}{5} \\ = 9.6MAD=n∑i=1n∣yt−Ft∣MAD=5∣57−63∣+∣60−72∣+∣70−86∣+∣75−71∣+∣70−60∣=56+12+16+4+10=9.6
Answer: option 2 is correct
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