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Question #225806
The random variable X is exponentially distributed with mean 3. Find P(X > t + 3|X > t)
where t is any positive real number.
Expert's answer
Gicen
X
∼
E
x
p
(
λ
)
,
μ
=
3
X\sim Exp(\lambda), \mu=3
X
∼
E
x
p
(
λ
)
,
μ
=
3
λ
=
1
μ
=
1
3
\lambda=\dfrac{1}{\mu}=\dfrac{1}{3}
λ
=
μ
1
=
3
1
By the Memoryless Property:
P
(
X
>
t
+
r
∣
X
>
t
)
=
P
(
X
>
r
)
,
r
≥
0
,
t
≥
0
P(X>t+r|X>t)=P(X>r), r\geq0, t\geq0
P
(
X
>
t
+
r
∣
X
>
t
)
=
P
(
X
>
r
)
,
r
≥
0
,
t
≥
0
Then
P
(
X
>
t
+
3
∣
X
>
t
)
=
P
(
X
>
3
)
P(X>t+3|X>t)=P(X>3)
P
(
X
>
t
+
3∣
X
>
t
)
=
P
(
X
>
3
)
=
e
−
3
(
1
3
)
=
e
−
1
≈
0.3679
=e^{-3({1 \over 3})}=e^{-1}\approx0.3679
=
e
−
3
(
3
1
)
=
e
−
1
≈
0.3679
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