Answer to Question #225805 in Statistics and Probability for Prathyush

Question #225805
(a) Give two examples of continuous time discrete state random processes.
(b) Find the mean, autocorrelation and autocovariance of the random process defined by X(t) =
A cos ωt, where A is uniformly distributed in (0,1) and ω is a constant.
1
Expert's answer
2021-08-16T09:44:07-0400

Part a)

Discrete-time continuous state Markov processes are widely used. Autoregressive processes are a very important example.

Actually, if you relax the Markov property and look at discrete-time continuous state stochastic processes in general, then this is the topic of study of a huge part of Time series analysis and signal processing.

The most famous examples are ARMA processes, the Conditionally Heteroscedastic models, a large subclass of Hidden Markov models


Part b)

Given, random process, X(t)=Kcos(wt)t0X(t) = Kcos(wt) t ≥ 0

The expected value of K is, E[K]=1+02=0.5E[K]=\frac{1+0}{2}=0.5

The variance of K is, σK2=(10)212=112\sigma_K^2 = \frac{(1-0)^2}{12}=\frac{1}{12}

Thus

E[K2]=σK2+[E[K]]2E[K2]=112+(0.5)2E[K2]=13E[K^2] = \sigma_K^2+ [E[K]]^2 \\ E[K^2] = \frac{1}{12} + (0.5)^2 \\ E[K^2] = \frac{1}{ 3}

The mean of X(t) is,

E[X(t)]=E[Kcos(wt)]E[X(t)]=E[K]cos(wt)E[X(t)]=12cos(wt)E[X(t)] = E[Kcos(wt)] \\ E[X(t)] = E[K]cos(wt) \\ E[X(t)] = \frac{1}{2} cos(wt)


The autocorrelation function of X(t) is,

Rxx(t,s)=E[X(t)X(s)]Rxx(t,s)=E[K2cos(wt)cos(ws)]Rxx(t,s)=E[K2]cos(wt)cos(ws)Rxx(t,s)=13cos(wt)cos(ws)R_{xx}(t, s) = E[X(t)X(s)] \\ R_{xx}(t, s) = E[K^2cos(wt)cos(ws)] \\ R_{xx}(t, s) = E[K^2]cos(wt)cos(ws)\\ R_{xx}(t, s) = \frac{1}{3} cos(wt)cos(ws)


The autocovariance function of X(t) is,

Cxx(t,s)=Rxx(t,s)E[X(t)]E[X(s)]Cxx(t,s)=13cos(wt)cos(ws)14cos(wt)cos(ws)Cxx(t,s)=112cos(wt)cos(ws)C_{xx}(t, s) = R_{xx}(t, s) — E[X(t)]E[X (s)]\\ C_{xx}(t, s) = \frac{1}{3}cos(wt)cos(ws) -\frac{1}{4} cos(wt)cos(ws)\\ C_{xx}(t, s) = \frac{1}{12}cos(wt)cos(ws)


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