A production lot of size 100 is known to be 55% defective. A random sample of 12
items is selected without replacement. Determine the probability that there will be
no defective in the sample.
Solution:
Required probability=45100×4499×4398×...×3489=0.00002738=\dfrac{45}{100}\times \dfrac{44}{99}\times \dfrac{43}{98}\times ...\times\dfrac{34}{89}=0.00002738=10045×9944×9843×...×8934=0.00002738
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