If the mean of a set of data is 24, and 18.40 has a z
-
score of
–
1.40, then the
variance must be:
Solution:
Given, μ=24,Xˉ=18.40,z=−1.40,σ=?\mu=24,\bar X=18.40,z=-1.40,\sigma=?μ=24,Xˉ=18.40,z=−1.40,σ=?
z=Xˉ−μσ⇒−1.40=18.40−24σ⇒σ=−5.6−1.40=4z=\dfrac{\bar X-\mu}{\sigma} \\ \Rightarrow-1.40=\dfrac{18.40-24}{\sigma} \\ \Rightarrow \sigma=\dfrac{-5.6}{-1.40}=4z=σXˉ−μ⇒−1.40=σ18.40−24⇒σ=−1.40−5.6=4
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