Answer to Question #224315 in Statistics and Probability for Harry

Question #224315

A sample of 200 tourists in Florida shows 52 went to Disney, 57 went to Busch Gardens, and 52 visited both. Find the probability that a tourist attended neither Disney nor Busch Gardens.


1
Expert's answer
2021-08-09T15:46:10-0400
P(DBG)=P(D)+P(BG)P(DBG)P(D\cup BG)=P(D)+P(BG)-P(D\cap BG)

=52200+5720052200=0.285=\dfrac{52}{200}+\dfrac{57}{200}-\dfrac{52}{200}=0.285




1P(DBG)=10.285=0.7151-P(D\cup BG)=1-0.285=0.715

The probability that a tourist attended neither Disney nor Busch Gardens is 0.715.0.715.



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