Question

The probability that a patients recovers from a rare blood disease is ‘0.a’. If 15

people are known to have contracted this disease. What is the probability that from 3

to ‘a’ survive?

• Where ‘a’ is 55

Answer 1

$P(X=3)=C_{15}^30.55^3(1-0.55)^{15-3}=0.0052.$