For a Normal distribution with mean, μ=2, and standard deviation, σ=4, 30% of all observations have a value less than
For a Normal distribution with mean, μ=2, and standard deviation, σ=4, 40% of all observations have a value greater than
For a normal distribution with mean, μ=2, and standard deviation, σ=4 what proportion of observations take values less than 1?
Can you also please explain how to get the answer?
1
Expert's answer
2013-01-18T08:57:58-0500
Let X be random variable having standard normaldistribution, that ismean μ=0, and standard deviation, σ=1.
Let also F be the cumulative distribution function for X,so F(t) = P(X<t) The values of function F are computed and can be found inany book on probability theory. So for problems 1)-3) we will use the values of functionF. Let Y be the random variable having Normal distributionwith mean, μ=2, and standard deviation, σ=4.In 1) and 2) we should find values y1, y2 such that 1) P(Y < y1) = 0.32) P(Y > y2) = 0.4 In 3) we should find probability 3) P(Y < 1). Consider the so called "normalized" randomvariable Z = (Y-μ)/σ =(Y-2)/4. Then Z has standard normal distribution and so P(Z<t) = F(t). Now we can solve 1)-3).1) 0.3 = P(Y<y1) = P((Y-2)/4 < (y1-2)/4 ) = P( Z <(y1-2)/4 ) = F( (y1-2)/4) From tables for F we obtain that F(-0.524) = 0.3 whence (y1-2)/4 = -0.542 Therefore y1 = -0.542*4+2=-0.168 Thus for a Normal distribution with mean, μ=2, andstandard deviation, σ=4, 30% of all observations have a value less than -0.1682)
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