Frequency distribution:
A – 22
B – 5
AB – 2
O – 21
Total 50
a. P(O)=2150=0.42P(O) = \frac{21}{50}=0.42P(O)=5021=0.42
b. P(A or B)=22+550=2750=0.54P(A \;or\; B) = \frac{22+5}{50}=\frac{27}{50}=0.54P(AorB)=5022+5=5027=0.54
c. P(neither A nor O)=5+250=750=0.14P(neither \;A \;nor\; O) = \frac{5+2}{50}= \frac{7}{50}= 0.14P(neitherAnorO)=505+2=507=0.14
d. P(not AB)=22+5+2150=4850=0.96P(not \;AB) = \frac{22+5+21}{50}= \frac{48}{50}=0.96P(notAB)=5022+5+21=5048=0.96
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