Assume that when adults with smartphones are randomly selected, 46% use them in meetings or classes. If 9 adult smartphone users are randomly selected, find the probability that exactly 4 of them use their smartphones in meetings or classes.
Let X be a random variable denoting the number of adults out of a randomly selected 9 people, who use their smartphones in meetings or classes. X has Binomial distribution with parameters "n=9", "p=0.44". This means that the probability that exactly "k" adults use their smartphones in meetings or classes is equal to "P(X=k)=\\binom{k}{n}p^k(1-p)^{n-k}".
Therefore, "P(X=4)=\\frac{9!}{4!5!}0.46^4\\cdot0.54^5=0.259".
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