Question #220905

Assume that when adults with smartphones are randomly​ selected, 46​% use them in meetings or classes. If 9 adult smartphone users are randomly​ selected, find the probability that exactly 4 of them use their smartphones in meetings or classes.


1
Expert's answer
2021-12-27T18:31:12-0500

Let X be a random variable denoting the number of adults out of a randomly selected 9 people, who use their smartphones in meetings or classes. X has Binomial distribution with parameters n=9n=9, p=0.44p=0.44. This means that the probability that exactly kk adults use their smartphones in meetings or classes is equal to P(X=k)=(kn)pk(1p)nkP(X=k)=\binom{k}{n}p^k(1-p)^{n-k}.

Therefore, P(X=4)=9!4!5!0.4640.545=0.259P(X=4)=\frac{9!}{4!5!}0.46^4\cdot0.54^5=0.259.


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