An item produced by a company is susceptible to two types
of defects namely, A and B. The probability that an item has defect A is 1/6. The probability that it has defect
B is 1/8 . Calculate the probability that the item has
1.(i) P=16∗18=148≈0.0208.P=\frac{1}{6}*\frac{1}{8}=\frac{1}{48}\approx0.0208.P=61∗81=481≈0.0208.
2.(ii) P=16∗(1−18)=748≈0.1458.P=\frac{1}{6}*(1-\frac{1}{8})=\frac{7}{48}\approx 0.1458.P=61∗(1−81)=487≈0.1458.
3(iii) P=18∗(1−16)=548≈0.1042.P=\frac{1}{8}*(1-\frac{1}{6})=\frac{5}{48}\approx0.1042.P=81∗(1−61)=485≈0.1042.
4(iv) P=748+548=1248=14=0.25.P=\frac{7}{48}+\frac{5}{48}=\frac{12}{48}=\frac{1}{4}=0.25.P=487+485=4812=41=0.25.
5.(v) P=1−56∗78=1−3548=1348≈0.2708.P=1-\frac{5}{6}*\frac{7}{8}=1-\frac{35}{48}=\frac{13}{48}\approx0.2708.P=1−65∗87=1−4835=4813≈0.2708.
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