The proportion if eligible voters in the next election who will vote for the ANC is assumed to 0.55 in Gauteng
Let "X" be a binomial rv based on "n" trials with success probability "p." Then if the binomial probability histogram is not too skewed, "X" has approximately a normal distribution with "\\mu=np" and "\\sigma^2=npq."
In practice, the approximation is adequate provided that both "np\\geq 10" and "nq\\geq 10."
Given "n=500, p=0.55, q=1-p=1-0.55=0.45."
Check "np=500(0.55)=275>10, nq=500(0.45)=225>10."
Then "\\mu=np=275, \\sigma^2=500(0.55)(0.45)=123.75."
"X\\sim N(275, 123.75)"
"p_1=0.49, 0.49(500)=245"
"\\approx P(Z<-2.6928)\\approx0.0035"
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