Question #219049

Let Z~N (0,1).Find a constant c for which P(-c≤ Z ≤ c) = 0.8664


1
Expert's answer
2021-07-23T12:01:01-0400

By condition, the mathematical expectation is a=0a=0 and the standard deviation is σ=1\sigma = 1 .

Then

P(cZc)=0.8664Φ(caσ)Φ(caσ)=0.8664Φ(c)Φ(c)=0.86642Φ(c)=0.8664Φ(c)=0.4332c=1.5P( - c \le Z \le c) = 0.8664 \Rightarrow \Phi \left( {\frac{{c - a}}{\sigma }} \right) - \Phi \left( {\frac{{ - c - a}}{\sigma }} \right) = 0.8664 \Rightarrow \Phi \left( c \right) - \Phi \left( { - c} \right) = 0.8664 \Rightarrow 2\Phi \left( c \right) = 0.8664 \Rightarrow \Phi \left( c \right) = 0.4332 \Rightarrow c = 1.5

Answer: c=1.5c=1.5


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