a document is equally likely to be in any of the 3 box files.a seach of ith the box will discover the document with probability pi. what is the probability that, the document is in the 1st box given that i have searched the first box twice and not found it
Solution:
There are 3 boxes.
The probability that document will be in any of them"=\\dfrac13"
Given, a search of ith box will discover the document with probability pi.
So, a search of 1st box will discover the document with probability = p(1)=p.
Now, the probability that, the document is in the 1st box given that I have searched the first box twice and not found it=P(the document is in the 1st box and I have searched the first box twice and not found it)/P(I have searched the first box twice and not found it)
"=\\dfrac{\\dfrac13}{(1-p)(1-p)}=\\dfrac{1}{3(1-p)^2}"
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