Answer to Question #218366 in Statistics and Probability for Leah

Question #218366
Use the table below to answer the questions that follow
X| 0 | 1| 2 | 3 | 4| 5|
Freq| 15| 24| 8| 6| 10| 4|

i) Use the table above to construct cumulative frequency and relative cumulative frequencies for the distribution
ii) Estimate the mean deviation
1
Expert's answer
2021-07-19T05:45:42-0400

Solution:

Mean=μ=ΣfixiΣfi=15×0+24×1+8×2+6×3+10×4+4×567Mean=\mu=\dfrac{\Sigma f_ix_i}{\Sigma f_i} \\=\dfrac{15\times 0+24\times 1+8\times 2+6\times 3+10\times 4+4\times 5}{67}

=0+24+16+18+40+2067=11867=1.76=\dfrac{0+24+16+18+40+20}{67} \\=\dfrac{118}{67}=1.76



Now, mean deviation

=ΣxiμΣfi=1.76+0.76+0.24+1.24+2.24+3.2467=0.14149=\dfrac{\Sigma|x_i -\mu|}{\Sigma f_i} \\=\dfrac{1.76+0.76+0.24+1.24+2.24+3.24}{67} \\=0.14149


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