"n_1 = 50 \\\\\n\nn_2=75 \\\\\n\n\\bar{x_1}=75 \\\\\n\ns_1=6 \\\\\n\n\\bar{x_2}= 82 \\\\\n\ns_2=2 \\\\\n\nH_0: \\mu_1 = \\mu_2 \\\\\n\nH_1: \\mu_1 \u2260 \\mu_2"
Test-statistic:
"Z = \\frac{\\bar{x_1} -\\bar{x_2}}{\\sqrt{ (s_1^2\/n_1)+(s^2_2\/n_2) }} \\\\\n\nZ= \\frac{75-82}{\\sqrt{ (6^2\/50) +(2^2\/75) }} = -7.96"
Let use 5 % significant level.
Two-tailed test.
Reject H0 if Z≤ -1.96 or Z≥1.96.
"Z= -7.96 < Z_{crit}= -1.96"
Reject H0.
There is enough evidence to conclude that there is any difference between the performance of boys and girls at 5% significant level.
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