Question #217897
Large Consignments of computer components are inspected for
defectives by means of a sampling system. Ten components are
examined and the lot is to be rejected if two or more are found
to be defective. If a consignments contains exactly 10%
defectives.
Find the probability of the consignment by using the technique
of Binomial probability distribution that the consignment is:
i) Accepted
ii) Rejected
1
Expert's answer
2021-07-19T07:32:15-0400

Binomial (10,0.1)

P(x)=(nx)Px(1P)nx,x=0,1,2,...,10P(x)=\binom{n}{x}P^x(1-P)^{n-x}, x=0,1,2,...,10

i. Probability of accepting is P(x1)P(x\le1)

P(x1)=P(x=0)+P(x=1)P(x\le1)=P(x=0)+P(x=1)

=[(100)×(10.1)10]+[(101)×0.11(10.1)9]=[\binom{10}{0}\times(1-0.1)^{10}]+[\binom{10}{1}\times0.1^1(1-0.1)^9]

=0.349+0.387=0.349+0.387

=0.736=0.736

ii. Probability of rejecting is P(x>1)P(x>1)

P(x>1)P(x>1) is 1- probability of accepting

P(x>1)=1P(x1)P(x>1)=1-P(x\le1)

=10.736=1-0.736

=0.264=0.264


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