Question

In a distribution, what is the range of the area within twice the standard deviation of the distribution curve , given mean=3.4, standard deviation=5

Answer 1

By the 68–95–99.7 rule

$$P(\mu-1\sigma<X<\mu+1\sigma)=0.6827$$

$$P(3.4-5<X<3.4+5)=0.6827$$