Answer to Question #217118 in Statistics and Probability for Hasan

Question

A sample of 10 networking sites for a specific month has a mean of 26.1 and a standard deviation of 4.2. Find the 99% confidence interval of the true mean.

Answer 1

$n=10 \\ \bar{x} =26.1 \\ s=4.2$

Two-sided confidence interval:

$CI = (\bar{x} - \frac{Z_c \times s}{\sqrt{n}}, \bar{x} + \frac{Z_c \times s}{\sqrt{n}}) \\ CI = (26.1 - \frac{2.576 \times 4.2}{\sqrt{10}}, 26.1 + \frac{2.576 \times 4.2}{\sqrt{10}}) \\ CI = (26.1 - 3.42, 26.1 + 3.42) \\ CI = (22.68, 29.52)$