Question #216251

random samples of size n=2 are drawn from a finite population consisting of the numbers 5,6,7,8,9. compute fot the mean, variance and standard deviation of the population, and the mean, variance and standard deviation of the mean


1
Expert's answer
2021-07-14T13:09:50-0400

The population values are 5,6,7,85, 6, 7, 8 andand 99.

The sample size n=2n=2 .


Populationmean=5+6+7+8+95Population\:mean=\frac{5+6+7+8+9}{5}

Populationmean=7Population\:mean=7


Variance=(57)2+(67)2+(77)2+(87)2+(97)25\:Variance=\frac{\left(5-7\right)^2+\left(6-7\right)^2+\left(7-7\right)^2+\left(8-7\right)^2+\left(9-7\right)^2}{5}

Variance=4+1+0+1+45Variance=\frac{4+1+0+1+4}{5}

Variance=2Variance=2


Standarddeviation=2Standard\:deviation=\sqrt{2} =1.41=1.41


The table for sampling distribution is shown below:




Thevarianceofsamplingdistribution=(5.57)+(67)+2(6.57)+2(77)+2(7.57)+(87)+(8.57)10The\:variance\:of\:sampling\:distribution=\frac{\left(5.5-7\right)+\left(6-7\right)+2\left(6.5-7\right)+2\left(7-7\right)+2\left(7.5-7\right)+\left(8-7\right)+\left(8.5-7\right)}{10}

Varianceofsamplingdistributionis=2.25+1+0.5+0+0.5+1+2.2510Variance\:of\:sampling\:distribution\:is\:=\frac{2.25+1+0.5+0+0.5+1+2.25}{10}

Varianceofsamplingdistributionis=0.75Variance\:of\:sampling\:distribution\:is\:=0.75


Samplestandarddeviation=0.75Sample\:standard\:deviation=\sqrt{0.75}

Samplestandarddeviation=0.86Sample\:standard\:deviation=0.86


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS