S={e1,e2,e3,e4}
Given,
P(e3)=31P(e2)=3P(e1)
Now,
P(e1)+P(e2)+P(e3)+P(e4)=1⟹P(e1)+P(e2)+P(e4)=1−31=32 ⟹P(e1)+3P(e1)+P(e4)=32 [∵P(e2)=3P(e1)] ⟹4P(e1)+P(e4)=32
Since, the value of P(e4) is not given , so we assume the value of P(e4)
Let P(e4)=61
So,
⟹4P(e1)=32−61=63=21 ⟹P(e1)=81
and
P(e2)=3P(e1)⟹P(e2)=83
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