Question #215627

Suppose that a factory has two machines, Machine A and Machine B, both producing iPhone touch screens. Forty percent of their touch screens come from Machine A and 60% of their touch screens come from Machine B. Ten percent of the touch screens produced by Machine A are defective and five percent of the touch screens from Machine B are defective. If I randomly choose a touch screen from those produced by both machines and find that it is defective, what is the probability that it came from machine A and also find the probability that it came from machine B ? 


1
Expert's answer
2021-07-16T02:43:18-0400

Let: AA touch screen produced by Machine A

BB touch screen produced by Machine B

DD touch screen is defective

Given

P(A)=0.4,P(B)=0.6,P(A)=0.4, P(B)=0.6,

P(DA)=0.1,P(DB)=0.05P(D|A)=0.1, P(D|B)=0.05

By Baye's Theorem the probability that defective touch screen came from machine A is


P(AD)=P(DA)P(A)P(DA)P(A)+P(DB)P(B)P(A|D)=\dfrac{P(D|A)P(A)}{P(D|A)P(A)+P(D|B)P(B)}

=0.1(0.4)0.1(0.4)+0.05(0.6)=47=\dfrac{0.1(0.4)}{0.1(0.4)+0.05(0.6)}=\dfrac{4}{7}

The probability that defective touch screen came from machine A is


P(BD)=P(DB)P(B)P(DA)P(A)+P(DB)P(B)P(B|D)=\dfrac{P(D|B)P(B)}{P(D|A)P(A)+P(D|B)P(B)}

=0.05(0.6)0.1(0.4)+0.05(0.6)=37=\dfrac{0.05(0.6)}{0.1(0.4)+0.05(0.6)}=\dfrac{3}{7}


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