My friend stella used to work in a taxi call centre . On any normal day she would expect to take 6calls every 10minutes.
Solution:
Given, λ=6 calls/10 min=0.6 calls/min\lambda=6\ calls/10\ min=0.6\ calls/ minλ=6 calls/10 min=0.6 calls/min
X∼Poi(λ)X\sim Poi(\lambda)X∼Poi(λ)
(1):
P(X=6)=e−6×666!=0.1606P(X=6)=e^{-6}\times\dfrac{6^6}{6!}=0.1606P(X=6)=e−6×6!66=0.1606
(2):
Between 10:23 and 10:28, the time duration is 5 minutes.
So, λ=3 calls/5 min\lambda=3\ calls/5\ minλ=3 calls/5 min
P(X=0)=e−3×300!=0.04978P(X=0)=e^{-3}\times\dfrac{3^0}{0!}=0.04978P(X=0)=e−3×0!30=0.04978
Now, required probability=1−0.04978=0.95022=1-0.04978=0.95022=1−0.04978=0.95022
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