Answer to Question #213317 in Statistics and Probability for lou

Question

Consider all samples of size of 5 from the population

2,5,7,9,10,11,12

Answer 1

N=7

n=5

Number of samples $= \frac{N!}{n!(N-n)!}$

$= \frac{7!}{5!(7-5)!}= \frac{6 \times 7}{2}= 21$