Question #212580

100, 100, 99, 98, 92, 91, 91, 90, 88, 87, 87, 85, 85, 85, 80, 79, 76, 72, 67, 66, 45

 

d)           James obtained a mark of 90 and Petrus obtained a mark of 79 for the test. How would you describe their results in relation to the mean? 



1
Expert's answer
2021-07-02T12:11:40-0400

d)


mean=μ=E(X)=121(100+100+99+98mean=\mu=E(X)=\dfrac{1}{21}(100+100+99+98

+92+91+91+90+88+87+87+85+92+91+91+90+88+87+87+85

+85+85+80+79+76+72+67+66+45)+85+85+80+79+76+72+67+66+45)

=83.95=83.95

James obtained a mark of 90 which is greater than the mean mark among 21 students.

Petrus obtained a mark of 79 which is less than the mean mark among 21 students.



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