two dice arr simultaneously rolled find probillity to getting sum of at least 11
There are "6 \\times 6 = 36" ways two dice could fall
There 3 ways (5+6, 6+5, 6+6) to get sum of at least 11
The probability to getting sum of at least 11
"P = \\frac{3}{36}= \\frac{1}{12}"
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