Question

two dice arr simultaneously rolled find probillity to getting sum of at least 11

Answer 1

There are $6 \times 6 = 36$ ways two dice could fall

There 3 ways (5+6, 6+5, 6+6) to get sum of at least 11

The probability to getting sum of at least 11

$P = \frac{3}{36}= \frac{1}{12}$