Answer to Question #211333 in Statistics and Probability for anuj

Question

A bag contains so many pink and yellow balls. A person can have 2 balls. Given that one of the balls is pink, what

is the probability that the other one is also pink?

(b) One hundred cars enter for a road-worthiness test which is in 2 parts mechanical and electrical. A car can only

pass if it passes both parts. Half the cars fail the electrical test and 62 pass the mechanical. 15 pass the electrical

and fail the mechanical test.

Find the probability that:

(i) A car chosen at random given that it has failed, failed the electrical test only

(ii) The Probability of fails on one test only will be

Answer 1

(a)

Let x be the number of pink balls.

Therefore there are x yellow balls in the bag .

$P(II pink | I pink)=\frac{n-1}{2n-1}$

(b)

Let mechanical test be B

Let electrical test be A

Therefore;

$N(B)=62,N(A)=50,N(A\bigcap B')=15.$

$N(B\bigcap A)=N(A)-N(A\bigcap B')=50-15=35$

$N(B\bigcap A')=N(B)-N(B\bigcap A)=62-35=27$

(i)

Prob (failed electric,passed mechanical)and prop(it failed at least one)

prop(it failed at least one ) $=\frac{100-35}{100}=\frac{65}{100}$

Prop(failed electric,passed mechanical)$=\frac{27}{100}$

$\because\frac{\frac{27}{100}}{\frac{65}{100}}=\frac{27}{65}$

(ii)

$P(B\bigcap A' orA\bigcap B')=\frac{27+15}{100}=0.42$