Question

A coin is tossed twice at random what is the probability of getting

(a)At least one tail

(b)The same face

Answer 1

Solution:

S={HH,HT,TH,TT}

(a) Event of at least one tail = {HT,TH,TT}

P(at least one tail)$=\dfrac{3}{4}$

(b) Event of the same face = {TT,HH}

P(The same face)$=\dfrac{2}{4}=\dfrac{1}{2}$