For the following probability distribution:
𝑓(𝑥) = 𝑘𝑒|𝑥|
, − ∞ ≤ 𝑥 ≤ ∞
Show that 𝑘 =
1
2
, 𝜇
′
1 = 0, 𝜎 = √2 and mean deviation about mean is 1.
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