Question #209949

Two balls are drawn in succession without replacement from an urn containing 4 red balls and 3 black balls. Find the probability distribution of the number of black balls.


Expert's answer

P(X=0)=4736=27.P(X=0)=\frac{4}{7}*\frac{3}{6}=\frac{2}{7}.

P(X=1)=4736+3746=47.P(X=1)=\frac{4}{7}*\frac{3}{6}+\frac{3}{7}*\frac{4}{6}=\frac{4}{7}.

P(X=0)=3726=17.P(X=0)=\frac{3}{7}*\frac{2}{6}=\frac{1}{7}.


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