Two balls are drawn in succession without replacement from an urn containing 4 red balls and 3 black balls. Find the probability distribution of the number of black balls.
P(X=0)=47∗36=27.P(X=0)=\frac{4}{7}*\frac{3}{6}=\frac{2}{7}.P(X=0)=74∗63=72.
P(X=1)=47∗36+37∗46=47.P(X=1)=\frac{4}{7}*\frac{3}{6}+\frac{3}{7}*\frac{4}{6}=\frac{4}{7}.P(X=1)=74∗63+73∗64=74.
P(X=0)=37∗26=17.P(X=0)=\frac{3}{7}*\frac{2}{6}=\frac{1}{7}.P(X=0)=73∗62=71.
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