Find the mean of probability distribution of the random variable X, which can take only the values 2,4,5 and 9, given that P(2) = 9/20, P(4) = 1/20 , P(5) = 1/5 , and P(9) = 3/10
E(x)=∑∀xxP(x)E(x)=\sum_{\forall x} xP(x)E(x)=∑∀xxP(x)
=2(920)+4(120)+5(15)+9(310)=2(\frac{9}{20})+4(\frac{1}{20})+5(\frac{1}{5})+9(\frac{3}{10})=2(209)+4(201)+5(51)+9(103)
=4.8=4.8=4.8
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