Question

Calculate the probability from the z-table. a. 𝑃(𝑍 > −0.45) b. 𝑃( 𝑍 < 2.10) c. 𝑃(0 < 𝑍 < 2.10) d. 𝑃(−0.45 < 𝑍 < 2.10)

Answer 1

a. 𝑃(𝑍 > −0.45) = $P(-0.45<Z<0)+P(0<Z<\infty)=0.17364+0.5=0.67364$

b. 𝑃( 𝑍 < 2.10) = $P(-\infty<Z<0)+P(0<Z<2.10)=0.5+0.48214=0.98214$

c. 𝑃(0 < 𝑍 < 2.10) =0.48214

d. 𝑃(−0.45 < 𝑍 < 2.10)=

$P(-0.45<Z<0)+P(0<Z<2.10)=0.17364+0.48214=0.65578$