Question #20859

compute standard error of estimate for data below
x values= 3,-2,2,5,10
y values= 4,6,-2,0,-3

Expert's answer

Conditions

compute standard error of estimate for data below

x values=3,-2,2,5,10

y values= 4,6,-2,0,-3

Solution

The formula for calculation of standard error:


SE=σnSE = \frac{\sigma}{\sqrt{n}}


where


σ=1Ni=1N(xiμ)2,whereμ=1Ni=1Nxi.\sigma = \sqrt{\frac{1}{N} \sum_{i=1}^{N} (x_i - \mu)^2}, \quad \text{where} \quad \mu = \frac{1}{N} \sum_{i=1}^{N} x_i.μx=15(32+2+5+10)=3,6\mu_x = \frac{1}{5} (3 - 2 + 2 + 5 + 10) = 3,6μy=15(4+62+03)=1\mu_y = \frac{1}{5} (4 + 6 - 2 + 0 - 3) = 1σx=15((33,6)2+(23,6)2+(23,6)2+(53,6)2+(103,6)2)=\sigma_x = \sqrt{\frac{1}{5} \left( (3 - 3,6)^2 + (-2 - 3,6)^2 + (2 - 3,6)^2 + (5 - 3,6)^2 + (10 - 3,6)^2 \right)} ==15(0.36+31,36+2,56+1,96+40,96)=15,443,929= \sqrt{\frac{1}{5} \left( 0.36 + 31,36 + 2,56 + 1,96 + 40,96 \right)} = \sqrt{15,44} \approx 3,929σy=15((41)2+(61)2+(21)2+(01)2+(31)2)=\sigma_y = \sqrt{\frac{1}{5} \left( (4 - 1)^2 + (6 - 1)^2 + (-2 - 1)^2 + (0 - 1)^2 + (-3 - 1)^2 \right)} ==15(9+25+9+1+16)=12=23= \sqrt{\frac{1}{5} (9 + 25 + 9 + 1 + 16)} = \sqrt{12} = 2\sqrt{3}SEx=3,92951,757SE_x = \frac{3,929}{\sqrt{5}} \approx 1,757SEy=2351,549SE_y = \frac{2\sqrt{3}}{\sqrt{5}} \approx 1,549

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