1. A jeepney driver claims that his average monthly income is Php 3000.00 with a standard deviation
of Php 300.00. A sample of 30 jeepney drivers were surveyed and found that their average monthly
income is Php 3500.00 with a standard deviation of Php 350.00. Test the hypothesis at 1% level of
significance
Solution:
Given, "\\mu=3000,n=30,\\sigma=350, \\bar X=3500"
At 1% significance level and df=29, t=2.462021
"H_0:\\mu=3000\n\\\\H_1:\\mu\\ne3000"
Now, "\\dfrac{\\bar X-\\mu}{\\sigma\/\\sqrt n}=\\dfrac{3500-3000}{350\/\\sqrt {30}}=7.824>2.462021"
"H_0" is rejected.
Thus, "\\mu\\ne3000"
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