Question #208322

Assume that the probability of a male birth is 1/2. Find the probability that in a family of 4 children there will be:


a) at least 1 boy and at least 1 girl. 


1
Expert's answer
2022-01-09T09:51:43-0500

P(0  boy)=0.54=0.0625.P(0\; boy)=0.5^4=0.0625.

P(0  girl)=0.54=0.0625.P(0\;girl)=0.5^4=0.0625.

P(at  least  1  boy  and  at  least  1  girl)=1P(0  boy)P(0  girl)=P( at\;least\;1\;boy\;and\;at\;least\;1\;girl)=1-P(0\;boy)-P(0\;girl)=

=10.06250.0625=0.875.=1-0.0625-0.0625=0.875.


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