Assume that the probability of a male birth is 1/2. Find the probability that in a family of 4 children there will be:
a) at least 1 boy and at least 1 girl.
P(0 boy)=0.54=0.0625.P(0\; boy)=0.5^4=0.0625.P(0boy)=0.54=0.0625.
P(0 girl)=0.54=0.0625.P(0\;girl)=0.5^4=0.0625.P(0girl)=0.54=0.0625.
P(at least 1 boy and at least 1 girl)=1−P(0 boy)−P(0 girl)=P( at\;least\;1\;boy\;and\;at\;least\;1\;girl)=1-P(0\;boy)-P(0\;girl)=P(atleast1boyandatleast1girl)=1−P(0boy)−P(0girl)=
=1−0.0625−0.0625=0.875.=1-0.0625-0.0625=0.875.=1−0.0625−0.0625=0.875.
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