Answer to Question #208061 in Statistics and Probability for jane

Question

independent random sample of size 9 is taken with replacement from a population with mean 25.2 and variance 12

Answer 1

$$\mu_{\bar{x}}=\mu=25.2$$

$$\sigma^2_{\bar{x}}=\dfrac{\sigma^2}{n}=\dfrac{12}{9}=\dfrac{4}{3}$$

$$\sigma_{\bar{x}}=\dfrac{\sigma}{\sqrt{n}}=\dfrac{\sqrt{12}}{\sqrt{9}}=\dfrac{2\sqrt{3}}{3}$$