(iii) During a laboratory experiment, the average number of radioactive particles passing through a counter in 1 millisecond is 2. What is the probability that 5 particles enter the counter in any given millisecond?
Poisson distribution
P(X=x)=e−λ×λxx!λ=2x=5P(X=5)=e−2×255!=0.03609P(X=x) = \frac{e^{-λ} \times λ^x }{x!} \\ λ=2 \\ x=5 \\ P(X=5) = \frac{e^{-2} \times 2^5 }{5!} \\ = 0.03609P(X=x)=x!e−λ×λxλ=2x=5P(X=5)=5!e−2×25=0.03609
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