(ii) If 1% of an airline’s flight suffers a minor equipment failure in an aircraft, what is the probability that there will be exactly 5 such in the next 1000 such flights?
If we use the approximation of binomial distribution by Poisson, then:
"\u03bb=np=0.01\u00d7(1000)=10."
"P(X=5)=\\dfrac{e^{-10}\\cdot10^5}{5!}\\approx0.0378."
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