even A and B are such that P(A U B )=0.76,P(B)=0.4 Given that A and B are non mutually exclusive events that are independent calculate P(A)
AAA and BBB are non mutually events: P(A∩B)≠0.P(A\cap B)\not=0.P(A∩B)=0.
AAA and BBB are independent events: P(A∩B)=P(A)P(B).P(A\cap B)=P(A)P(B).P(A∩B)=P(A)P(B).
P(A)=0.6P(A)=0.6P(A)=0.6
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