The probability that a vehicle entering the Luray Caverns has Canadian
license plates is 0.12; the probability that it is a camper is 0.28; and the
probability that it is a camper with Canadian license plates is 0.09. What is
the probability that
(i) A camper entering the Luray Caverns has Canadian license Plates.
(ii) A vehicle with Canadian license plates entering the Luray Caverns is a
camper.
(iii) A vehicle entering the Luray Caverns does not have Canadian plates or
is not a camper.
Solution
Let C denote the probability that a vehicle entering the Cavern has Canadian licence plates
"P(C)=0.12"
Let R denote the probability that it is a camper
"P(R) = 0.28"
The probability that it is a camper with Canadian plate license is
"P(C\\bigcap R)= 0.09"
I) probability that a camper entering the Lurray has Canadian license plates
"P(C\/R) = \\frac{P(C\\bigcap R)}{P(R)}"
"\\frac{0.09}{0.28} = 0.321"
ii) To find probability that a vehicle with Canadian License plates entering the Lurray Cavern is a camper
we need to find;
"P(R\/C) = \\frac{P(R\\bigcap C)}{P(C)}"
"\\frac{0.09}{0.12} = 0.75"
iii) Probability that a vehicle entering the Luray Cavern does not have Canadian plates and is not a camper, We need to find
"P(C'\\bigcup R')"
"1-P(C\\bigcap R)"
"1-0.09"
"=0.91"
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