Assume that X has the exponential distribution with parameter : Is it possible to find a function G .x/ such that Y D G .X/ has uniform distribution over [0; 1]? Justify your answer!
The exponential distribution has probability density function "\\lambda e^{-\\lambda Y}"
and cumulative distribution function (CDF) "1-e^{-\\lambda Y}"
We map the unit interval onto the range of the CDF. Then, inverting the CDF, we get
"Y=-\\frac{ln(1-X)}{\\lambda}" for 0≤X<1 (we can ignore 1 because it occurs with probability 0).
So the function is (with λ=1)
"g(X)=\u2212ln(1\u2212X)"
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