On a test in Statistics, the mean is 45 and the standard deviation is 5. Assuming normality, what is the standard score of a student who receives a score of 40?
μ=45σ=5Z−score=45−405=1\mu=45 \\ \sigma=5 \\ Z-score =\frac{45-40}{5}=1μ=45σ=5Z−score=545−40=1
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