Question

Suppose your class of Management got the following results in Spring 2020 (one record for each student) Table 3: Result of marketing students

Student Id

Communication Skills

Punctuality

Class Participation

Final

1

25

19.4

10.4

4.2

2

23

2.3

2.2

2.4

3

10.5

1.9

7.1

6.1

4

7.2

1.4

4.3

8.2

5

3.7

7.9

8.5

2.2

6

5.1

7.6

10.6

9.9

7

7.2

2.3

8.8

6.4

8

10.1

3.2

6.9

4.8

 

a.   Using k-means clustering, divide the data into twi groups.  Show your calculations up to two iterations.

b.   What analysis do you make after performing this descriptive data mining step? Discuss the basic characteristics of each of these two groups of students

Answer 1

$a.\\ \text{k-mean}=\dfrac{240.8}{8}=30.1\\ \text{Now, only student id 1 and 6 have higher total value(59, 33.2) than k-mean.}\\ \text{So the required two groups will be :- $\{1,6\}$ and $\{2,3,4,5,7,8\}$.}$

$b.\\ \text{Out of 8 students, only 2 students are selected as above average.}\\ \text{Remaining 6 students are not only below average, they have bad performance also. These 6 students have scored very less in Punctuality which implies they are irregular too. But student 5 have good Punctuality and Class participation.}$