In a sample of 300 students, 68% said they own an iPod and a smart phone. Compute a 95% confidence interval for the true percent of students who own an iPod and a smartphone.
"p=0.68 \\\\\n\nq=1-p=1-0.68=0.32 \\\\\n\nCI \\; 0.95 \\\\\n\n\u03b1=1-0.95=0.05 \\\\\n\n\\frac{\u03b1}{2}=0.025 \\\\\n\nZ_{0.025}=1.959 \\\\\n\nCI = p \u00b1Z_{0.025} \\sqrt{\\frac{pq}{n}} \\\\\n\n= 0.68 \u00b1 1.959 \\times \\sqrt{\\frac{0.68 \\times 0.32}{300}} \\\\\n\n= 0.68 \u00b10.052"
CI: 0.628 ≤ p ≤0.732
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