A normal distribution has μ = 80 and σ = 10. What is the probability of randomly selecting between the mean and a score of 90
"P(80<X<90)=P(\\frac{80-80}{10}<Z<\\frac{90-80}{10})=P(0<Z<1)="
"=P(Z<1)-P(Z<0)=0.8413-0.5=0.3413."
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