Question #20238

A husband and wife have three children. The outcome of the first child being a boy, the second a girl, and the third a girl can be represented by BGG. Determine each of the following:

a)sample space that describes all the orders of the possible genders of the children
b)the event that at least one child is a girl
c)the event that at least one child is boy
d)is the event in part (C) the complement of the event in part ((b)?

Expert's answer

Conditions

A husband and wife have three children. The outcome of the first child being a boy, the second a girl, and the third a girl can be represented by BGG. Determine each of the following:

a) sample space that describes all the orders of the possible genders of the children

b) the event that at least one child is a girl

c) the event that at least one child is boy

d) is the event in part (C) the complement of the event in part ((b)?

Solution

a) The sample space is:

BBB,BBG,BGB,BGG,GBB,GGG,GBG

b) The event is at least 1 child is a girl is the opposite event to the event of 3 boys.

The probability of 3 boys will be is 18\frac{1}{8}, then the probability of at least 1 girl is 118=78\frac{1 - 1}{8} = \frac{7}{8}

c) The event of one child is a boy is the same (18\frac{1}{8}), because the probability to have boy or girl in each of 3 moments is 12\frac{1}{2}.

d) The event of at least 1 girl and at least 1 boy is the opposite to event "all 3 boys or all 3 girls".

The probability of 3 boys is 18\frac{1}{8}, of 3 girls is 18\frac{1}{8}. Then of BBB or GGG is 18+18=14\frac{1}{8} + \frac{1}{8} = \frac{1}{4}.

And the probability of at least 1 girl and at least 1 boy is 114=34\frac{1 - 1}{4} = \frac{3}{4}.

Answer:

a) BBB,BBG,BGB,BGG,GBB,GGG,GBG

b) 18\frac{1}{8}

c) 18\frac{1}{8}

d) 34\frac{3}{4}

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