Question #202175

1. A radioactive particle is randomly located in a square area with sides that are 1 unit in length. Let X and Y denote the coordinates of the particle. Because the particle is equally likely to fall in any subarea of fixed size, a reasonable model of (X , Y ) is given by


a. Find the mean of X.

b. Find the mean of Y.

c. Find the covariance between X and Y.

d. Find the correlation between X and Y.


1
Expert's answer
2021-06-03T07:08:35-0400

Solution:

f(x,y)={1,0x1,0y10, elsewhere f1(x)=1f2(y)=1\begin{array}{ll} f(x, y)=\left\{\begin{array}{ll} 1, & & 0 \leq x \leq 1,0 \leq y \leq 1 \\ 0, & \text { elsewhere } \end{array}\right. \\ & f_{1}\left({x}\right)=1 \\ & f_{2}\left(y\right)=1 \end{array}

The expected value is the sum of the product of each possibility with its probability:

(a) E(X)=E(Y)=+xf(x)dx=01x(1)dx=12E\left(X\right)=E\left(Y\right)=\int_{-\infty}^{+\infty} x f(x) d x=\int_{0}^{1} x(1) d x=\frac{1}{2}

(b) E(Y)=12E(Y)=\frac12

(c) Then we get,

E(XY)=E(X)E(Y)=12×12=14E\left(XY\right)=E\left(X\right) E\left(Y\right)=\frac{1}{2} \times \frac{1}{2}=\frac{1}{4}

Cov(XY)=E(XY)E(X)E(Y)=1412.12=0Cov(XY)=E(XY)-E(X)E(Y)=\dfrac14-\dfrac12.\dfrac12=0

(d) Correlation(XY)=Cov(XY)σXσY=0Correlation(XY)=\dfrac{Cov(XY)}{\sigma_X\sigma_Y}=0


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