A family has 3 boys and 5 girls. In how many ways can their parents choose a basketball team of 5 people? Include evidence of your work by typing our your solution.
The total number of children is 3 + 5 = 8
Formula for combinations is "\\frac{n!}{((n-x)!\\times{x!})}" , where n is a total number of permutations of a set (8), and x is a number of children in a team (5)
So the solution is "\\frac{8!}{(8-5)!\\times{5!}}=56"
Answer: 56 ways.
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