Question

A family has 3 boys and 5 girls. In how many ways can their parents choose a basketball team of 5 people? Include evidence of your work by typing our your solution.

Answer 1

The total number of children is 3 + 5 = 8

Formula for combinations is $\frac{n!}{((n-x)!\times{x!})}$ , where n is a total number of permutations of a set (8), and x is a number of children in a team (5)

So the solution is $\frac{8!}{(8-5)!\times{5!}}=56$

Answer: 56 ways.