Answer to Question #201469 in Statistics and Probability for Homam

Question #201469

The following data represents the students' scores :


(81,35,86,91,69,72,47,66,80,55,90,53,43,56,80,77,59)

Wanted to find:


standard deviation


1
Expert's answer
2021-06-02T06:39:10-0400

Standard deviation:

σ=(xix)2N\sigma=\sqrt{\frac{\sum(x_i-\overline{x})^2}{N}}

Mean:

x=xiN\overline{x}=\frac{\sum x_i}{N}


x=114017=67\overline{x}=\frac{1140}{17}=67


σ=142+322+192+242+22+52+202+1+132+122+232+142+242+112+132+102+8217=465517=16.55\sigma=\sqrt{\frac{14^2+32^2+19^2+24^2+2^2+5^2+20^2+1+13^2+12^2+23^2+14^2+24^2+11^2+13^2+10^2+8^2}{17}}=\sqrt{\frac{4655}{17}}=16.55


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